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{{General relativity}}
== eyes not on Ao unknown one ==
In the [[mathematical]] field of [[differential geometry]], the '''Riemann curvature tensor''', or '''Riemann–Christoffel tensor''' after [[Bernhard Riemann]] and [[Elwin Bruno Christoffel]], is the most standard way to express [[curvature of Riemannian manifolds]].  It associates a [[tensor]] to each point of a [[Riemannian manifold]] (i.e., it is a [[tensor field]]), that measures the extent to which the [[metric tensor]] is not locally isometric to a Euclidean space.  The curvature tensor can also be defined for any [[pseudo-Riemannian manifold]], or indeed any manifold equipped with an [[affine connection]].  It is a central mathematical tool in the theory of [[general relativity]], the modern theory of [[gravity]], and the curvature of [[spacetime]] is in principle observable via the [[geodesic deviation equation]].  The curvature tensor represents the [[tidal force]] experienced by a rigid body moving along a [[geodesic]] in a sense made precise by the [[Jacobi field|Jacobi equation]].


The curvature tensor is given in terms of the [[Levi-Civita connection]] <math>\nabla</math> by the following formula:
Once upon a Maronite forces will be comparable, which comes in [http://www.lamartcorp.com/modules/mod_menu/rakuten_cl_14.php クリスチャンルブタン メンズ 靴] really claim to be [http://www.lamartcorp.com/modules/mod_menu/rakuten_cl_13.php クリスチャンルブタン] a nameless and Yu Huang a [http://www.lamartcorp.com/modules/mod_menu/rakuten_cl_13.php クリスチャンルブタン] level figures. '<br><br>Jun Bald also the channel: 'it is strange to say, extremely powerful Dragon Dragon Emperor strength, being super animal cairica, and another eight demon emperor, but also has a Maronite heritage treasures, even if he is strong. , but he and an ordinary dragon born two sons are also very weird o '<br><br>'born two sons?' Qin Yu puzzled.<br><br>eyes not on Ao unknown one, Is there a brother?<br><br>'Qin Yu, you should know cairica Dragon is very rare, and even cairica itself, he is [http://www.lamartcorp.com/modules/mod_menu/rakuten_cl_14.php クリスチャンルブタン アウトレット] the son hardly cairica!'<br><br>'I know.' Qin Yu this or know.<br><br>cairica is random, there may be a dragon and a black dragon child, it may be some other dragons to children. This [http://www.lamartcorp.com/modules/mod_menu/rakuten_cl_8.php クリスチャンルブタン スニーカー] is random, but the probability is lower than one million points.<br>After all, the whole<br>
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:<math>R(u,v)w=\nabla_u\nabla_v w - \nabla_v \nabla_u w - \nabla_{[u,v]} w</math>
== with Gorefiend Duzhong Jun Hua Yan conversation ==


where [''u'',''v''] is the [[Lie bracket of vector fields]]. For each pair of tangent vectors ''u'', ''v'',  ''R''(''u'',''v'') is a linear transformation of the tangent space of the manifold. It is linear in ''u'' and ''v'', and so defines a tensorOccasionally, the curvature tensor is defined with the opposite sign.
Casual magic party, the party and the Dragon are Sanxian flew [http://www.lamartcorp.com/modules/mod_menu/rakuten_cl_6.php クリスチャンルブタン スニーカー] towards the south, and toward the ancient prehistoric Yao Zu Chuan Songzhen direction is flying, and Qin Yu, black feathers, [http://www.lamartcorp.com/modules/mod_menu/rakuten_cl_5.php クリスチャンルブタン 偽物] Hou fees. Lan wind. Such as a group [http://www.lamartcorp.com/modules/mod_menu/rakuten_cl_0.php クリスチャンルブタン 価格] of people were dead standing volley watched these people to leave.<br><br>breeze blowing, let Qin Yu hair blowing swing in the corner.<br><br>Qin Yu homeport down the empty black blood, and real good.<br><br>but at the moment the blood and black empty real good and positive, respectively, with Gorefiend Duzhong Jun Hua Yan conversation, that smile face looked [http://www.lamartcorp.com/modules/mod_menu/rakuten_cl_6.php クリスチャンルブタン アウトレット] very humble.<br><br>'Slowly talk about it, you do not have much of the day.' Qin Yu heart says [http://www.lamartcorp.com/modules/mod_menu/rakuten_cl_3.php クリスチャンルブタン 東京] slowly.<br><br>'Qin Yu little brother.'<br><br>'ah?' Qin Yu from thinking awakened, looked up. Qin Yu were dead are laughing.<br><br>'I do not know what things were older?' Qin Yu convergence of mind.<br><br>were dead nodded and smiled: 'I am also here to stay for a relatively long period of time, choose a day as collision, today I am ready to riot Xinghai people you want to let us go back to the front when.
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If <math>u=\partial/\partial x^i</math> and <math>v=\partial/\partial x^j</math> are coordinate vector fields then <math>[u,v]=0</math> and therefore the formula simplifies to 
== read the latest text version of the novel ==
:<math>R(u,v)w=\nabla_u\nabla_v w - \nabla_v \nabla_u w .</math>
The curvature tensor measures ''noncommutativity of the covariant derivative'', and as such is the [[integrability condition|integrability obstruction]] for the existence of an isometry with Euclidean space (called, in this context, ''flat'' space).  The linear transformation <math>w\mapsto R(u,v)w</math> is also called the '''curvature transformation''' or '''endomorphism'''.


The curvature formula can also be expressed in terms of the [[second covariant derivative]] defined as:<ref name="lawson">{{cite book | last1=Lawson | first1=H. Blaine, Jr. | last2=Michelsohn | first2=Marie-Louise|author2-link=Marie-Louise Michelsohn | title=Spin Geometry | year=1989| page=154 | publisher=Princeton U Press | isbn=0-691-08542-0 }}</ref>
Baby body movement, eyes full of excitement, excited.<br>Happy Senior<br>but also to restrain myself, did not rush to.<br><br>, read the latest text version of the novel<br><br>'Brother!' Hou Fei looked over. Qin Yu is not even in the past, could not help frowning, 'Brother, do you stand so far away, come, come, take a look at these two little dolls, ha ha.' Hou [http://www.lamartcorp.com/modules/mod_menu/rakuten_cl_6.php クリスチャンルブタン 銀座] Fei who look only at the Happy Senior's passing, although surprised by this I have never seen one, but Hou Fei [http://www.lamartcorp.com/modules/mod_menu/rakuten_cl_4.php クリスチャンルブタン通販] did not care.<br><br>saw Red Cloud, Daisy duo came out from the house, as the [http://www.lamartcorp.com/modules/mod_menu/rakuten_cl_8.php クリスチャンルブタン 直営店] master of the gods, which did not affect on [http://www.lamartcorp.com/modules/mod_menu/rakuten_cl_8.php クリスチャンルブタン スニーカー] the body giving birth. That Hongyun more directly greeting: 'Monkey, the 'Myolie' to me.'<br><br>'Hou apricot? The name did not sound ah, my land lady ah, such a lovely daughter called what Hou apricot, or listen to me, called Hou sweet bar. sweet, much better.' Hou Fei immediately said.<br><br>'Poof!'<br><br>suddenly a group of [http://www.lamartcorp.com/modules/mod_menu/rakuten_cl_6.php クリスチャンルブタン アウトレット] people laughed, Qin Yu, black feather
 
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: <math>\nabla^2_{u,v} w = \nabla_u\nabla_v w - \nabla_{\nabla_u v} w </math>
<ul>
 
 
which is linear in ''u'' and ''v''. Then:
  <li>[http://www.goodchoiceflowers.com/cgi-bin/store/index.cgi http://www.goodchoiceflowers.com/cgi-bin/store/index.cgi]</li>
 
 
: <math>R(u,v)=\nabla^2_{u,v} - \nabla^2_{v,u} </math>
  <li>[http://www.vaswim.org/cgi-bin/rcalc.cgi http://www.vaswim.org/cgi-bin/rcalc.cgi]</li>
 
 
Thus in the general case of non-coordinate vectors ''u'' and ''v'', the curvature tensor measures the noncommutativity of the second covariant derivative.
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==Geometrical meaning==
  </ul>
===Informally===
Imagine walking around the bounding white line of a tennis court with a stick held out in front of you. When you reach the first corner of the court, you turn to follow the white line, but you keep the stick held out in the same direction, which means you are now holding the stick out to your side. You do the same when you reach each corner of the court. When you get back to where you started, you are holding the stick out in exactly the same direction as you were when you started (no surprise there).
 
Now imagine you are standing on the equator of the earth, facing north with the stick held out in front of you. You walk north up along a line of longitude until you get to the north pole. At that point you turn right, ninety degrees, but you keep the stick held out in the same direction, which means you are now holding the stick out to your left. You keep walking (south obviously – whichever way you set off from the north pole, it's south) until you get to the equator. There, you turn right again (and so now you have to hold the stick pointing out behind you) and walk along the equator until you get back to where you started from. But here is the thing: the stick is pointing back along the equator from where you just came, not north up to the pole how it was when you started!
 
The reason for the difference is that the surface of the earth is curved, but a tennis court is flat, but it is not quite that simple. Imagine that the tennis court is slightly humped along its centre-line so that it is like part of the surface of a cylinder. If you walk around the court again, the stick still points in the same direction as it did when you started. The reason is that the humped tennis court has ''extrinsic'' curvature but no ''intrinsic'' curvature. The surface of the earth, however, has both extrinsic and intrinsic curvature.
 
The Riemann curvature tensor is a way to capture a measure of the intrinsic curvature. When you write it down in terms of its components (like writing down the components of a vector), it consists of a multi-dimensional array of sums and products of partial derivatives (some of those partial derivatives can be thought of as akin to capturing the curvature imposed upon someone walking in straight lines on a curved surface).
 
===Formally===
When a vector in a Euclidean space is [[parallel transport]]ed around a loop, it will again point in the initial direction after returning to its original position. However, this property does not hold in the general case. The Riemann curvature tensor directly measures the failure of this in a general [[Riemannian manifold]]. This failure is known as the non-[[holonomy]] of the manifold. 
 
Let ''x''<sub>''t''</sub> be a curve in a Riemannian manifold ''M''.  Denote by τ<sub>''x''<sub>''t''</sub></sub> : T<sub>x<sub>0</sub></sub>''M'' → T<sub>x<sub>t</sub></sub>''M'' the parallel transport map along ''x''<sub>t</sub>. The parallel transport maps are related to the [[covariant derivative]] by
:<math>\nabla_{\dot{x}_0} Y = \lim_{h\to 0} \frac{1}{h}\left(Y_{x_0}-\tau^{-1}_{x_h}(Y_{x_h})\right) = \left.\frac{d}{dt}(\tau_{x_t}Y)\right|_{t=0}</math>
for each [[vector field]] ''Y'' defined along the curve.
 
Suppose that ''X'' and ''Y'' are a pair of commuting vector fields.  Each of these fields generates a pair of one-parameter groups of diffeomorphisms in a neighborhood of ''x''<sub>0</sub>.  Denote by τ<sub>tX</sub> and τ<sub>tY</sub>, respectively, the parallel transports along the flows of ''X'' and ''Y'' for time ''t''. Parallel transport of a vector ''Z'' ∈ T<sub>x<sub>0</sub></sub>''M'' around the quadrilateral with sides ''tY'', ''sX'', &minus;''tY'', &minus;''sX'' is given by
:<math>\tau_{sX}^{-1}\tau_{tY}^{-1}\tau_{sX}\tau_{tY}Z.</math>
This measures the failure of parallel transport to return ''Z'' to its original position in the tangent space T<sub>x<sub>0</sub></sub>''M''. Shrinking the loop by sending ''s'', ''t'' → 0 gives the infinitesimal description of this deviation:
:<math>\left.\frac{d}{ds}\frac{d}{dt}\tau_{sX}^{-1}\tau_{tY}^{-1}\tau_{sX}\tau_{tY}Z\right|_{s=t=0} = (\nabla_X\nabla_Y - \nabla_Y\nabla_X)Z = R(X,Y)Z</math>
where ''R'' is the Riemann curvature tensor.
 
==Coordinate expression==
Converting to the [[tensor index notation]], the Riemann curvature tensor is given by
:<math>R^\rho{}_{\sigma\mu\nu} = dx^\rho(R(\partial_{\mu},\partial_{\nu})\partial_{\sigma})</math>
where <math>\partial_{\mu} = \partial/\partial x^{\mu}</math> are the coordinate vector fields. The above expression can be written using [[Christoffel symbols]]:
:<math>R^\rho{}_{\sigma\mu\nu} = \partial_\mu\Gamma^\rho{}_{\nu\sigma}
    - \partial_\nu\Gamma^\rho{}_{\mu\sigma}
    + \Gamma^\rho{}_{\mu\lambda}\Gamma^\lambda{}_{\nu\sigma}
    - \Gamma^\rho{}_{\nu\lambda}\Gamma^\lambda{}_{\mu\sigma}</math>
 
(see also the [[list of formulas in Riemannian geometry]]).
 
The Riemann curvature tensor is also the [[commutator]] of the covariant derivative of an arbitrary covector <math>A_{\nu}\,</math>
with itself:<ref>{{cite book |author=Synge J.L., Schild A. |title=Tensor Calculus |publisher=first Dover Publications 1978 edition |pages=83; 107 |year=  1949
|isbn=978-0-486-63612-2}}</ref><ref>{{cite book |author=P. A. M. Dirac| title=General Theory of Relativity| publisher=Princeton University Press | year=1996| isbn=0-691-01146-X}}</ref>
:<math>A_{\nu ; \rho \sigma} - A_{\nu ; \sigma \rho} = A_{\beta} R^{\beta}{}_{\nu \rho \sigma} \, ,</math>
since the [[Connection (mathematics)|connection]] <math>\Gamma^\alpha{}_{\beta\mu}\,</math> is torsionless, which means that the [[torsion tensor]] <math>\Gamma^\lambda{}_{\mu\nu}-\Gamma^\lambda{}_{\nu\mu}\,</math> vanishes.
 
This formula is often called the ''Ricci identity''.<ref name="lovelockrund">{{cite book | last=Lovelock | first=David | coauthors=Hanno Rund | title=Tensors, Differential Forms, and Variational Principles | year= 1989 |page=84; 109 | origyear=1975 | publisher=Dover | isbn=978-0-486-65840-7}}</ref> This is the classical method used by [[Gregorio Ricci-Curbastro|Ricci]] and [[Tullio Levi-Civita|Levi-Civita]] to obtain an expression for the Riemann curvature tensor.<ref>{{citation|title=Méthodes de calcul différentiel absolu et leurs applications|last=Ricci|first=Gregorio|author-link=Gregorio Ricci-Curbastro|last2=Levi-Civita|first2=Tullio |journal=Mathematische Annalen |publisher=Springer |volume=54 |issue=1–2 |date=March 1900 |pages=125–201|doi=10.1007/BF01454201|url=http://www.springerlink.com/content/u21237446l22rgg7/fulltext.pdf}}</ref> In this way, the tensor character of the set of quantities <math>R^{\beta}{}_{\nu \rho \sigma}\,</math> is proved.
 
This identity can be generalized to get the commutators for two covariant derivatives of arbitrary tensors as follows
:<math> \begin{align}
T^{\alpha_1 \cdots \alpha_r}{}_{\beta_1 \cdots \beta_s ; \gamma \delta} - T^{\alpha_1 \cdots \alpha_r}{}_{\beta_1 \cdots \beta_s ; \delta \gamma} = \, & - R^{\alpha_1}{}_{\rho \gamma \delta} T^{\rho \alpha_2 \cdots \alpha_r}{}_{\beta_1 \cdots \beta_s} - \cdots - R^{\alpha_r}{}_{\rho \gamma \delta} T^{\alpha_1 \cdots \alpha_{r-1} \rho}{}_{\beta_1 \cdots \beta_s} \\
& + \, R^\sigma{}_{\beta_1 \gamma \delta} T^{\alpha_1 \cdots \alpha_r}{}_{\sigma \beta_2 \cdots \beta_s} + \cdots + R^\sigma{}_{\beta_s \gamma \delta} T^{\alpha_1 \cdots \alpha_r}{}_{\beta_1 \cdots \beta_{s-1} \sigma} \,.
\end{align}</math>
This formula also applies to [[tensor density|tensor densities]] without alteration, because for the Levi-Civita (''not generic'') connection one gets:<ref name="lovelockrund"/>
:<math>\nabla_{\mu}(\sqrt{g}\,)\equiv (\sqrt{g}\,)_{;\mu}=0 \, ,
\quad {\mathrm{where}} \quad {g}=|{\mathrm{det}}(g_{\mu\nu})|\, .</math>
 
It is sometimes convenient to also define the purely covariant version by
:<math>R_{\rho\sigma\mu\nu} = g_{\rho \zeta} R^\zeta{}_{\sigma\mu\nu} \,.</math>
 
==Symmetries and identities==
The Riemann curvature tensor has the following symmetries:
:<math>R(u,v)=-R(v,u)^{}_{}</math>
:<math>\langle R(u,v)w,z \rangle=-\langle R(u,v)z,w \rangle^{}_{}</math>
:<math>R(u,v)w+R(v,w)u+R(w,u)v=0 ^{}_{}.</math>
 
The last identity was discovered by [[Gregorio Ricci-Curbastro|Ricci]], but is often called the '''first Bianchi identity''' or '''algebraic Bianchi identity''', because it is equivalent to the [[Luigi Bianchi|Bianchi]] identity below. (Also, if there is nonzero [[Torsion tensor|torsion]], the first Bianchi identity becomes a differential identity of the [[torsion tensor]].)
These three identities form a complete list of symmetries of the curvature tensor, i.e. given any tensor which satisfies the identities above, one can find a Riemannian manifold with such a curvature tensor at some point. Simple calculations show that such a tensor has <math>n^2(n^2-1)/12</math> independent components.
 
Yet another useful identity follows from these three:
:<math>\langle R(u,v)w,z \rangle=\langle R(w,z)u,v \rangle^{}_{}.</math>
 
On a Riemannian manifold one has the covariant derivative <math> \nabla_u R </math> and the [[Bianchi identity]] (often called the second Bianchi identity or differential Bianchi identity) takes the form:
   
:<math>(\nabla_uR)(v,w)+(\nabla_vR)(w,u)+(\nabla_w R)(u,v) = 0.</math>
 
Given any [[coordinate chart]] about some point on the manifold, the above identities may be written in terms of the components of the Riemann tensor at this point as:
 
;Skew symmetry
::<math>R_{abcd}^{}=-R_{bacd}=-R_{abdc}</math>
 
;Interchange symmetry
::<math>R_{abcd}^{}=R_{cdab}</math>
 
;First Bianchi identity
::<math>R_{abcd}+R_{acdb}+R_{adbc}^{}=0</math>
:This is often written
::<math>R_{a[bcd]}^{}=0,</math>
:where the brackets denote the [[antisymmetric tensor|antisymmetric part]] on the indicated indices. This is equivalent to the previous version of the identity because the Riemann tensor is already skew on its last two indices.
 
;Second Bianchi identity
::<math>R_{abcd;e}^{}+R_{abde;c}^{}+R_{abec;d}^{}=0</math>
:The semi-colon denotes a covariant derivative. Equivalently,
::<math>R_{ab[cd;e]}^{}=0</math>
:again using the antisymmetry on the last two indices of ''R''.
 
The algebraic symmetries are also equivalent to saying that ''R'' belongs to the image of the [[Young symmetrizer]] corresponding to the partition 2+2.
 
==Special cases==
;Surfaces
For a two-dimensional [[surface]], the Bianchi identities imply that the  Riemann tensor can be expressed  as
 
:<math>R_{abcd}^{}=K(g_{ac}g_{db}- g_{ad}g_{cb}) \, </math>
 
where <math>g_{ab}</math> is the [[metric tensor]] and <math>K</math> is a function called the [[Gaussian curvature]] and ''a'', ''b'', ''c'' and ''d'' take values either 1 or&nbsp;2. The Riemann tensor has only one functionally independent component. The Gaussian curvature coincides with the [[sectional curvature]] of the surface. It is also exactly half the [[scalar curvature]] of the 2-manifold, while the [[Ricci curvature]] tensor of the surface is simply given by
 
:<math>\operatorname{Ric}_{ab} = Kg_{ab}. \, </math>
 
;Space forms
A Riemannian manifold is a [[space form]] if its [[sectional curvature]] is equal to a constant ''K''. The Riemann tensor of a space form is given by
 
:<math>R_{abcd}^{}=K(g_{ac}g_{db}-g_{ad}g_{cb}).</math>
 
Conversely, except in dimension 2, if the curvature of a Riemannian manifold has this form for some function ''K'', then the Bianchi identities imply that ''K'' is constant and thus that the manifold is (locally) a space form.
 
==See also==
*[[Introduction to mathematics of general relativity]]
*[[Ricci decomposition|Decomposition of the Riemann curvature tensor]]
*[[Curvature of Riemannian manifolds]]
 
==Notes==
{{reflist}}
 
==References==
*{{citation|first=A.L.|last=Besse|title=Einstein manifolds|publisher=Springer|year=1987}}
*{{citation|first1=S.|last1=Kobayashi|first2=K.|last2=Nomizu|title=Foundations of differential geometry | volume=vol. 1 |publisher=Interscience|year=1963}}
* {{Citation | first1=Charles W. | last1=Misner | authorlink1=Charles W. Misner | first2=Kip S. | last2=Thorne | authorlink2=Kip S. Thorne | first3=John A. | last3=Wheeler | authorlink3=John Archibald Wheeler | title=[[Gravitation (book)|Gravitation]] | publisher= W. H. Freeman | year=1973 | isbn=0-7167-0344-0}}
 
{{Curvature}}
{{theories of gravitation}}
{{tensors}}
 
{{DEFAULTSORT:Riemann Curvature Tensor}}
[[Category:Tensors in general relativity]]
[[Category:Curvature (mathematics)]]
[[Category:Riemannian geometry]]

Revision as of 21:02, 12 February 2014

eyes not on Ao unknown one

Once upon a Maronite forces will be comparable, which comes in クリスチャンルブタン メンズ 靴 really claim to be クリスチャンルブタン a nameless and Yu Huang a クリスチャンルブタン level figures. '

Jun Bald also the channel: 'it is strange to say, extremely powerful Dragon Dragon Emperor strength, being super animal cairica, and another eight demon emperor, but also has a Maronite heritage treasures, even if he is strong. , but he and an ordinary dragon born two sons are also very weird o '

'born two sons?' Qin Yu puzzled.

eyes not on Ao unknown one, Is there a brother?

'Qin Yu, you should know cairica Dragon is very rare, and even cairica itself, he is クリスチャンルブタン アウトレット the son hardly cairica!'

'I know.' Qin Yu this or know.

cairica is random, there may be a dragon and a black dragon child, it may be some other dragons to children. This クリスチャンルブタン スニーカー is random, but the probability is lower than one million points.
After all, the whole
相关的主题文章:

with Gorefiend Duzhong Jun Hua Yan conversation

Casual magic party, the party and the Dragon are Sanxian flew クリスチャンルブタン スニーカー towards the south, and toward the ancient prehistoric Yao Zu Chuan Songzhen direction is flying, and Qin Yu, black feathers, クリスチャンルブタン 偽物 Hou fees. Lan wind. Such as a group クリスチャンルブタン 価格 of people were dead standing volley watched these people to leave.

breeze blowing, let Qin Yu hair blowing swing in the corner.

Qin Yu homeport down the empty black blood, and real good.

but at the moment the blood and black empty real good and positive, respectively, with Gorefiend Duzhong Jun Hua Yan conversation, that smile face looked クリスチャンルブタン アウトレット very humble.

'Slowly talk about it, you do not have much of the day.' Qin Yu heart says クリスチャンルブタン 東京 slowly.

'Qin Yu little brother.'

'ah?' Qin Yu from thinking awakened, looked up. Qin Yu were dead are laughing.

'I do not know what things were older?' Qin Yu convergence of mind.

were dead nodded and smiled: 'I am also here to stay for a relatively long period of time, choose a day as collision, today I am ready to riot Xinghai people you want to let us go back to the front when. 相关的主题文章:

read the latest text version of the novel

Baby body movement, eyes full of excitement, excited.
Happy Senior
but also to restrain myself, did not rush to.

, read the latest text version of the novel

'Brother!' Hou Fei looked over. Qin Yu is not even in the past, could not help frowning, 'Brother, do you stand so far away, come, come, take a look at these two little dolls, ha ha.' Hou クリスチャンルブタン 銀座 Fei who look only at the Happy Senior's passing, although surprised by this I have never seen one, but Hou Fei クリスチャンルブタン通販 did not care.

saw Red Cloud, Daisy duo came out from the house, as the クリスチャンルブタン 直営店 master of the gods, which did not affect on クリスチャンルブタン スニーカー the body giving birth. That Hongyun more directly greeting: 'Monkey, the 'Myolie' to me.'

'Hou apricot? The name did not sound ah, my land lady ah, such a lovely daughter called what Hou apricot, or listen to me, called Hou sweet bar. sweet, much better.' Hou Fei immediately said.

'Poof!'

suddenly a group of クリスチャンルブタン アウトレット people laughed, Qin Yu, black feather 相关的主题文章: