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This article describes periodic points of some complex quadratic maps. A map is a formula for computing a value of a variable based on its own previous value or values; a quadratic map is one that involves the previous value raised to the powers one and two; and a complex map is one in which the variable is a complex number. A periodic point of a map is a value of the variable that occurs repeatedly after intervals of a fixed length.

This theory is applied in relation with the theories of Fatou and Julia sets.

Definitions

Let

fc(z)=z2+c

where z and c are complex-valued. (This  f is the complex quadratic mapping mentioned in the title.) This article explores the periodic points of this mapping - that is, the points that form a periodic cycle when  f is repeatedly applied to them.

 fc(k)(z) is the  k -fold compositions of fc with itself = iteration of function fc or,

 fc(k)(z)=fc(fc(k1)(z))

Periodic points of a complex quadratic mapping of period  p are points  z of the dynamical plane such that :

 z:fc(p)(z)=z

where  p is the smallest positive integer.

We can introduce a new function:

 Fp(z,f)=fc(p)(z)z

so periodic points are zeros of function  Fp(z,f) :

 z:Fp(z,f)=0

which is a polynomial of degree  =2p

Stability of periodic points (orbit) - multiplier

Stability index of periodic points along horizontal axis
boundaries of regions of parameter plane with attracting orbit of periods 1-6
Critical orbit of discrete dynamical system based on complex quadratic polynomial. It tends to weakly attracting fixed point with abs(multiplier)=0.99993612384259

The multiplier ( or eigenvalue, derivative ) m(f,z0)=λ of rational map f at fixed point z0 is defined as :

m(f,z0)=λ={fc(z0),if z01fc(z0),if z0=

where fc(z0) is first derivative of  fc with respect to z at z0.

Because the multiplier is the same at all periodic points, it can be called a multiplier of periodic orbit.

Multiplier is:

  • complex number,
  • invariant under conjugation of any rational map at its fixed point[1]
  • used to check stability of periodic (also fixed) points with stability index : abs(λ)

Periodic point is :[2]

Where do periodic points belong?

  • attracting is always in Fatou set
  • repelling is in the Julia set
  • Indifferent fixed points may be in the one or in the other.[3] Parabolic periodic point is in Julia set.

Period-1 points (fixed points)

Finite fixed points

Let us begin by finding all finite points left unchanged by 1 application of f. These are the points that satisfy  fc(z)=z. That is, we wish to solve

z2+c=z

which can be rewritten

 z2z+c=0.

Since this is an ordinary quadratic equation in 1 unknown, we can apply the standard quadratic solution formula. Look in any standard mathematics textbook, and you will find that there are two solutions of  Ax2+Bx+C=0 are given by

x=B±B24AC2A

In our case, we have A=1,B=1,C=c, so we will write

α1=114c2 and α2=1+14c2.

So for cC[1/4,+inf] we have two finite fixed points α1 and α2.

Since

α1=12m and α2=12+m where m=14c2

then α1+α2=1.

It means that fixed points are symmetrical around z=1/2.

This image shows fixed points (both repelling)

Complex dynamics

Fixed points for c along horizontal axis
Fatou set for F(z)=z*z with marked fixed point

Here different notation is commonly used:[4]

αc=114c2 with multiplier λαc=114c

and

βc=1+14c2 with multiplier λβc=1+14c

Using Viète's formulas one can show that:

αc+βc=BA=1

Since derivative with respect to z is :

Pc(z)=ddzPc(z)=2z

then

Pc(αc)+Pc(βc)=2αc+2βc=2(αc+βc)=2

It implies that Pc can have at most one attractive fixed point.

This points are distinguished by the facts that:

  • βc is :
    • the landing point of external ray for angle=0 for cM{14}
    • the most repelling fixed point, belongs to Julia set,
    • the one on the right ( whenever fixed point are not symmetrical around the real axis), it is the extreme right point for connected Julia sets (except for cauliflower).[5]
  • αc is:
    • landing point of several rays
    • is :
      • attracting when c is in main cardioid of Mandelbrot set, then it is in interior of Filled-in Julia set, it means belongs to Fatou set ( strictly to basin of attraction of finite fixed point )
      • parabolic at the root point of the limb of Mandelbrot set
      • repelling for other c values

Special cases

An important case of the quadratic mapping is c=0. In this case, we get α1=0 and α2=1. In this case, 0 is a superattractive fixed point, and 1 belongs to the Julia set.

Only one fixed point

We might wonder what value c should have to cause α1=α2. The answer is that this will happen exactly when 14c=0. This equation has 1 solution: c=1/4 (in which case, α1=α2=1/2). This is interesting, since c=1/4 is the largest positive, purely real value for which a finite attractor exists.

Infinite fixed point

We can extend complex plane to Riemann sphere (extended complex plane) ̂ by adding infinity

̂={}

and extend polynomial fc such that fc()=

Then infinity is :

fc()==fc1()

Period-2 cycles

Bifurcation from period 1 to 2 for complex quadratic map

Suppose next that we wish to look at period-2 cycles. That is, we want to find two points β1 and β2 such that fc(β1)=β2, and fc(β2)=β1.

Let us start by writing fc(fc(βn))=βn, and see where trying to solve this leads.

fc(fc(z))=(z2+c)2+c=z4+2z2c+c2+c.

Thus, the equation we wish to solve is actually z4+2cz2z+c2+c=0.

This equation is a polynomial of degree 4, and so has 4 (possibly non-distinct) solutions. However, actually, we already know 2 of the solutions. They are α1 and α2, computed above. It is simple to see why this is; if these points are left unchanged by 1 application of f, then clearly they will be unchanged by 2 applications (or more).

Our 4th-order polynomial can therefore be factored in 2 ways :

First method

(zα1)(zα2)(zβ1)(zβ2)=0.

This expands directly as x4Ax3+Bx2Cx+D=0 (note the alternating signs), where

D=α1α2β1β2
C=α1α2β1+α1α2β2+α1β1β2+α2β1β2
B=α1α2+α1β1+α1β2+α2β1+α2β2+β1β2
A=α1+α2+β1+β2.

We already have 2 solutions, and only need the other 2. This is as difficult as solving a quadratic polynomial. In particular, note that

α1+α2=114c2+1+14c2=1+12=1

and

α1α2=(114c)(1+14c)4=12(14c)24=11+4c4=4c4=c.

Adding these to the above, we get D=cβ1β2 and A=1+β1+β2. Matching these against the coefficients from expanding f, we get

D=cβ1β2=c2+c and A=1+β1+β2=0.

From this, we easily get : β1β2=c+1 and β1+β2=1.

From here, we construct a quadratic equation with A=1,B=1,C=c+1 and apply the standard solution formula to get

β1=134c2 and β2=1+34c2.

Closer examination shows (the formulas are a tad messy) that :

fc(β1)=β2 and fc(β2)=β1

meaning these two points are the two halves of a single period-2 cycle.

Second method of factorization

(z2+c)2+cz=(z2+cz)(z2+z+c+1)

The roots of the first factor are the two fixed points z1,2 . They are repelling outside the main cardioid.

The second factor has two roots

z3,4=12±(34c)12.

These two roots form period-2 orbit.[7]

Special cases

Again, let us look at c=0. Then

β1=1i32 and β2=1+i32

both of which are complex numbers. By doing a little algebra, we find |β1|=|β2|=1. Thus, both these points are "hiding" in the Julia set. Another special case is c=1, which gives β1=0 and β2=1. This gives the well-known superattractive cycle found in the largest period-2 lobe of the quadratic Mandelbrot set.

Cycles for period>2

There is no general solution in radicals to polynomial equations of degree five or higher, so it must be computed using numerical methods.

References

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  1. Alan F. Beardon, Iteration of Rational Functions, Springer 1991, ISBN 0-387-95151-2, p. 41
  2. Alan F. Beardon, Iteration of Rational Functions, Springer 1991, ISBN 0-387-95151-2, page 99
  3. Some Julia sets by Michael Becker
  4. On the regular leaf space of the cauliflower by Tomoki Kawahira Source: Kodai Math. J. Volume 26, Number 2 (2003), 167-178.
  5. Periodic attractor by Evgeny Demidov
  6. R L Devaney, L Keen (Editor): Chaos and Fractals: The Mathematics Behind the Computer Graphics. Publisher: Amer Mathematical Society July 1989, ISBN 0-8218-0137-6 , ISBN 978-0-8218-0137-6
  7. Period 2 orbit by Evgeny Demidov