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The maximum coverage problem is a classical question in computer science and computational complexity theory. It is a problem that is widely taught in approximation algorithms.

As input you are given several sets and a number $k$. The sets may have some elements in common. You must select at most $k$ of these sets such that the maximum number of elements are covered, i.e. the union of the selected sets has maximal size.

Formally, (unweighted) Maximum Coverage

Instance: A number $k$ and a collection of sets $S=S_{1},S_{2},\ldots ,S_{m}$.

Objective: Find a subset $S^{'}\subseteq S$ of sets, such that $\left|S^{'}\right|\leq k$ and the number of covered elements $\left|\bigcup _{S_{i}\in S^{'}}{S_{i}}\right|$ is maximized.

The maximum coverage problem is NP-hard, and cannot be approximated within $1-{\frac {1}{e}}+o(1)\approx 0.632$ under standard assumptions. This result essentially matches the approximation ratio achieved by the generic greedy algorithm used for maximization of submodular functions with a cardinality constraint.

ILP formulation

The maximum coverage problem can be formulated as the following integer linear program.

maximize $\sum _{e_{j}\in E}y_{j}$. (maximizing the sum of covered elements).

subject to $\sum {x_{i}}\leq k$; (no more than $k$ sets are selected).

$\sum _{\,e_{j}\in S_{i}}x_{i}\geq y_{j}$; (if $y_{j}\geq 0$ then at least one set $e_{j}\in S_{i}$ is selected).

$0\leq y_{j}\leq 1$; (if $y_{j}=1$ then $e_{j}$ is covered)

$x_{i}\in \{0,1\}$ (if $x_{i}=1$ then $S_{i}$ is selected for the cover).

Greedy algorithm

The greedy algorithm for maximum coverage chooses sets according to one rule: at each stage, choose a set which contains the largest number of uncovered elements. It can be shown that this algorithm achieves an approximation ratio of $1-{\frac {1}{e}}$. Inapproximability results show that the greedy algorithm is essentially the best-possible polynomial time approximation algorithm for maximum coverage.

Known extensions

The inapproximability results apply to all extensions of the maximum coverage problem since they hold the maximum coverage problem as a special case.

Weighted version

In the weighted version every element $e_{j}$ has a weight $w(e_{j})$. The task is to find a maximum coverage which has maximum weight. The basic version is a special case when all weights are $1$.

maximize $\sum _{e\in E}w(e_{j})\cdot y_{j}$. (maximizing the weighted sum of covered elements).

subject to $\sum {x_{i}}\leq k$; (no more than $k$ sets are selected).

$\sum _{e_{j}\in S_{i}}x_{i}\geq y_{j}$; (if $y_{j}\geq 0$ then at least one set $e_{j}\in S_{i}$ is selected).

$0\leq y_{j}\leq 1$; (if $y_{j}=1$ then $e_{j}$ is covered)

$x_{i}\in \{0,1\}$ (if $x_{i}=1$ then $S_{i}$ is selected for the cover).

The greedy algorithm for the weighted maximum coverage at each stage chooses a set which contains the maximum weight of uncovered elements. This algorithm achieves an approximation ratio of $1-{\frac {1}{e}}$.

Budgeted maximum coverage

In the budgeted maximum coverage version, not only does every element $e_{j}$ have a weight $w(e_{j})$, but also every set $S_{i}$ has a cost $c(S_{i})$. Instead of $k$ that limits the number of sets in the cover a budget $B$ is given. This budget $B$ limits the weight of the cover that can be chosen.

maximize $\sum _{e\in E}w(e_{j})\cdot y_{j}$. (maximizing the weighted sum of covered elements).

subject to $\sum {c(S_{i})\cdot x_{i}}\leq B$; (the cost of the selected sets cannot exceed $B$).

$\sum _{e_{j}\in S_{i}}x_{i}\geq y_{j}$; (if $y_{j}\geq 0$ then at least one set $e_{j}\in S_{i}$ is selected).

$0\leq y_{j}\leq 1$; (if $y_{j}=1$ then $e_{j}$ is covered)

$x_{i}\in \{0,1\}$ (if $x_{i}=1$ then $S_{i}$ is selected for the cover).

A greedy algorithm will no longer produce solutions with a performance guarantee. Namely, the worst case behavior of this algorithm might be very far from the optimal solution. The approximation algorithm is extended by the following way. First, after finding a solution using the greedy algorithm, return the better of the greedy algorithm's solution and the set of largest weight. Call this algorithm the modified greedy algorithm. Second, starting with all possible families of sets of sizes from one to (at least) three, augment these solutions with the modified greedy algorithm. Third, return the best out of all augmented solutions. This algorithm achieves an approximation ratio of $1-1/e$. This is the best possible approximation ratio unless $NP\subseteq DTIME(n^{O(\log \log n)})$.

Generalized maximum coverage

In the generalized maximum coverage version every set $S_{i}$ has a cost $c(S_{i})$, element $e_{j}$ has a different weight and cost depending on which set covers it. Namely, if $e_{j}$ is covered by set $S_{i}$ the weight of $e_{j}$ is $w_{i}(e_{j})$ and its cost is $c_{i}(e_{j})$. A budget $B$ is given for the total cost of the solution.

maximize $\sum _{e\in E,S_{i}}w_{i}(e_{j})\cdot y_{ij}$. (maximizing the weighted sum of covered elements in the sets in which they are covered).

subject to $\sum {c_{i}(e_{j})\cdot y_{ij}}+\sum {c(S_{i})\cdot x_{i}}\leq B$; (the cost of the selected sets cannot exceed $B$).

$\sum _{i}y_{ij}\leq 1$; (element $e_{j}=1$ can only be covered by at most one set).

$\sum _{S_{i}}x_{i}\geq y_{ij}$; (if $y_{j}\geq 0$ then at least one set $e_{j}\in S_{i}$ is selected).

$y_{ij}\in \{0,1\}$; (if $y_{ij}=1$ then $e_{j}$ is covered by set $S_{i}$)

$x_{i}\in \{0,1\}$ (if $x_{i}=1$ then $S_{i}$ is selected for the cover).

Generalized maximum coverage algorithm

The algorithm uses the concept of residual cost/weight. The residual cost/weight is measured against a tentative solution and its the difference of the cost/weight from the cost/weight gained by a tentative solution.

The algorithm has several stages. First, find a solution using greedy algorithm. In each iteration of the greedy algorithm the tentative solution is added the set which contains the maximum residual weight of elements divided by the residual cost of these elements along with the residual cost of the set. Second, compare the solution gained by the first step to the best solution which uses a small number of sets. Third, return the best out of all examined solutions. This algorithm achieves an approximation ratio of $1-1/e-o(1)$.

Related problems

• Set cover problem is to cover all elements with as few sets as possible.

References

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• Uriel Feige, A Threshold of ln $n$ for Approximating Set Cover, Journal of the ACM (JACM), v.45 n.4, p. 634 - 652, July 1998.